Typescript simple call back function

Question

In typescript what is the simplest way to make a function wait for a callback function within?

public isLoggedIn() : boolean
{
    myCallBackFunction.getItem(access_token).then((value) => {
        return value;
    });

}

This of course doesn't compile, but how do I make it wait for the result?

Possible duplicate of https://stackoverflow.com/questions/14220321/how-do-i-return-the-response-from-an-asynchronous-call — JohnnyHK, Jan 11 '17 at 01:37
The async concepts are the same whether it's ajax or any other async callback. Update your question with what you're trying that isn't working. See also http://stackoverflow.com/questions/23667086/why-is-my-variable-unaltered-after-i-modify-it-inside-of-a-function-asynchron. — JohnnyHK, Jan 11 '17 at 03:10

score 0 · Answer 1 · answered Jan 11 '17 at 15:00

I am afraid but there is no such way.

If the api you are using does not provide you with synchronous counterpart of asynchronous function (in your case its getItem), you are forced to use it in asynchronous way either by consuming promises directly or using async/await.

Typescript simple call back function

1 Answers1