Java Regex how to get all the matching occurences of a pattern

Asked Jan 11 '17 at 08:47

Active Jan 11 '17 at 08:50

Viewed 28 times

Here is the string

abcd&fq=-(( +ExpirationDate:[* TO *]  -ExpirationDate:[2016-12-13T08:00:00Z TO *]))&fq=-SupplierId:\"systemid:1000008557\"&fq=-Id:\"systemid:1000009073\"&rows=20&arches.preview=false&sort=score desc,DefaultRelevance desc&bmf=50&wt=text";

Would like to get the below as the output

fq=-(( +ExpirationDate:[* TO *]  -ExpirationDate:[2016-12-13T08:00:00Z TO *]))

fq=-Id:\"systemid:1000008557\"&fq=-Id:\"systemid:1000009073\"

Tried as below

String regex = "fq=.*&";
Pattern p = Pattern.compile(regex);
matcher = p.matcher(str);
while (matcher.find()) {
            System.out.println(matcher.group());
}

But got output as

fq=-SupplierId:\"systemid:1000008557\"&fq=-Id:\"systemid:1000009073\"&rows=20&arches.preview=false&sort=score desc,DefaultRelevance desc&bmf=50&

edited Jan 11 '17 at 08:50

asked Jan 11 '17 at 08:47

Raj

1

That's because `*` is greedy. Change to `fq=([^&]+)` – Maroun Jan 11 '17 at 08:49
@MarounMaroun why not put that as an answer? – Baby Jan 11 '17 at 08:52
@Baby Found a duplicate, prefer to close. – Maroun Jan 11 '17 at 08:53
Or [My regex is matching too much. How do I make it stop?](http://stackoverflow.com/questions/22444/my-regex-is-matching-too-much-how-do-i-make-it-stop) – Wiktor Stribiżew Jan 11 '17 at 08:56

Java Regex how to get all the matching occurences of a pattern

0 Answers0