How can I print the most common element of a list without importing a library?
l=[1,2,3,4,4,4]
So I want the output to be 4.
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jonrsharpe
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vasilistheod
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I'm brand-new here,i've not get used to this type of asking.I'm sorry.Could you please answer my question? – vasilistheod Jan 12 '17 at 11:50
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2No. Because **this isn't a code-writing service**. Learn [ask], and actually put in some effort yourself before dumping it on SO. – jonrsharpe Jan 12 '17 at 11:57
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2Possible duplicate of [Python most common element in a list](http://stackoverflow.com/questions/1518522/python-most-common-element-in-a-list) – CaptainObvious Jan 12 '17 at 11:59
2 Answers
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You can get the unique values first:
l = [1, 2, 3, 4, 4, 4]
s = set(l)
then you can create list of (occurrences, value) tuples
freq = [(l.count(i), i) for i in s] # [(1, 1), (1, 2), (1, 3), (3, 4)]
get the "biggest" element (biggest number of occurrences, the biggest value if there are more than one with the same number of occurrences):
result = max(freq) # (3, 4)
and print the value:
print(result[1]) # 4
or as a "one-liner" way:
l = [1, 2, 3, 4, 4, 4]
print(max((l.count(i), i) for i in set(l))[1]) # 4
Doncho Gunchev
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RakhamTheRed
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`max((l.count(i), i) for i in set(l))[1]`, no need to check extra values using range. – Doncho Gunchev Sep 01 '22 at 18:36
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1Yes absolutely, thanks for making the code better and your explanations. – RakhamTheRed Sep 02 '22 at 08:11
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lst=[1,2,2,2,3,3,4,4,5,6]
from collections import Counter
Counter(lst).most_common(1)[0]
Counter(lst) returns a dict of element-occurence pairs. most_common(n) returns the n most common elements from the dict, along with the number of occurences.
Anomitra
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