Block scope in js

Question

I was playing aroun and found interessting thing

var x = "x";
function a (){
    var x = "y";
  if(1){
    var x = "g";
    alert(x);
  }
  alert(x)
}

a()

why does this output "g" , "g" insted of "g" , "y" ? The if creates another block scope and x is local variable inside it which means when i get out of the if block , the outer x ( which equals "y" ) should be printed.

Please search google. This has been answered many times. Also for block scope, use `let`. variables declared with `var` are hoisted — Rajesh, Jan 12 '17 at 11:56
Variable hoisting http://stackoverflow.com/q/7506844/2942475 — Rishabh, Jan 12 '17 at 11:58

score 0 · Answer 1 · answered Jan 12 '17 at 12:21

0

The reason is the variable x has a function level scope and the latest value set to the variable is "g". And so you it alerted twice with same value of x "g".

answered Jan 12 '17 at 12:21

Macfer Ann

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Block scope in js

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