Get rid of zeros in python

Question

I wrote a very simple code in Python. I need to print all the numbers between 1 and 5 (including 1 and 5) in steps of 0.1. The integers should be without the suffix .0, i.e. the output should be:

0
0.1
0.2
...
1
1.1
...
...
5

Here is my code:

for i in range(0,51):
    if i%10==0:
        z=int(i/10)
        print (z)
    else:
        print (i*0.1)

Here is my output:

0
0.1
0.2
0.30000000000000004
0.4
0.5
0.6000000000000001
0.7000000000000001
0.8
0.9
1
1.1
1.2000000000000002
1.3
1.4000000000000001
1.5
1.6
1.7000000000000002
1.8
1.9000000000000001
2
2.1
2.2
2.3000000000000003
2.4000000000000004
2.5
2.6
2.7
2.8000000000000003
2.9000000000000004
3
3.1
3.2
3.3000000000000003
3.4000000000000004
3.5
3.6
3.7
3.8000000000000003
3.9000000000000004
4
4.1000000000000005
4.2
4.3
4.4
4.5
4.6000000000000005
4.7
4.800000000000001
4.9
5

I don't need all this zeros .000000001.

Or use the [`decimal`](https://docs.python.org/3/library/decimal.html) module — Patrick Haugh, Jan 13 '17 at 14:23

Mike Müller · Accepted Answer · 2017-01-13T14:57:22.607

Taking advantage of Python's string formatting capabilities, you can reduce your whole loop to one line:

for i in range(0, 51):
    print('{:.{deci}f}'.format(i*0.1, deci=min(1, i%10)))

Output:

0
0.1
0.2
...
0.8
0.9
1
1.1
1.2
...
1.8
1.9
2
2.1
2.2
...
4.8
4.9
5

Explanation

This gives you 0 for multiples of 10 for i and 1 for others:

>>> i = 10
>>>  min(1, i%10)
0
>>> i = 8
>>> min(1, i%10)
1

Now, you can use this for the keyword argument deci to determine the number of decimals in your output:

>>> '{:.{deci}f}'.format(1.99, deci=1)
'2.0'
>>> '{:.{deci}f}'.format(1.99, deci=0)
'2'

score 1 · Answer 2 · answered Jan 13 '17 at 14:23

You can print the floating point numbers rounded to 1 digit after the decimal point like so:

d = 1.12343214 
"{:.1f}".format(d)
>> 1.1

The second line formats d as a string representation of a float number rounded with 1 digit(comming from the .1) after the decimal point.

score 1 · Answer 3 · answered Jan 13 '17 at 14:23

1

You could use round or format

for i in range(0,51):
    if i%10==0:
        z=int(i/10)   
    else:
        z= (i*0.1)
    print '%.1f' % round(z, 1)
    print format(z, '.1f')

answered Jan 13 '17 at 14:23

Shijo

9,313
3
19
31

Please note this code will not work in python 3 – Ivaylo Strandjev Jan 13 '17 at 14:23

Maddy · Answer 4 · 2017-01-13T14:30:46.627

1

for i in range(0,51):
    if i%10==0:
        z=int(i/10)
        print (z)
    else:
        print ("%.1f" % (i*0.1))

you can use the %.1f notation. That will limit the number of decimals to be printed

OUTPUT

0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
1.1
1.2
1.3
1.4
1.5
1.6
1.7
1.8
1.9
2
2.1
2.2
2.3
2.4
2.5
2.6
2.7
2.8
2.9
3
3.1
3.2
3.3
3.4
3.5
3.6
3.7
3.8
3.9
4
4.1
4.2
4.3
4.4
4.5
4.6
4.7
4.8
4.9
5

edited Jan 13 '17 at 14:30

answered Jan 13 '17 at 14:24

Maddy

2,025
5
26
59

score 1 · Answer 5 · answered Jan 13 '17 at 14:27

1

Change your last line into:

print ( "%.1f" % (i*0.1) )

This will format your numbers showing only one decimal position.

answered Jan 13 '17 at 14:27

xzoert

308
1
6

score 1 · Answer 6 · answered Jan 13 '17 at 14:27

for i in range(0,51):
    if i%10==0:
        z= round(i/10)
        print (z)
    else:
        i = i * 0.1
        print ("%.1f" % i)

Output:

0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
1.1
1.2
1.3
1.4
1.5
1.6
1.7
1.8
1.9
2
2.1
2.2
2.3
2.4
2.5
2.6
2.7
2.8
2.9
3
3.1
3.2
3.3
3.4
3.5
3.6
3.7
3.8
3.9
4
4.1
4.2
4.3
4.4
4.5
4.6
4.7
4.8
4.9
5

Get rid of zeros in python

6 Answers6

Explanation