Undefined variable 'token'

Asked Jan 13 '17 at 15:29

Active Jan 13 '17 at 15:42

Viewed 25 times

What am I doing wrong here?

<?php

session_start();
$con = mysqli_connect("localhost", "root", "password", "db");

if (!isset($_SESSION['lodge'])) {
    header("Location: lodge.php");
}
$token = mysqli_real_escape_string($con, $_POST['token']);
$res = mysqli_query($con, "SELECT * FROM lodges WHERE lodge_id=" . $_SESSION['lodge']); 
$row = mysqli_fetch_array($res);
if ($row['token'] == ($token)) {
    $_SESSION['lodge'] = $row['lodge_id'];
    header('location:lodge.php');
}

?>

I keep getting the undefined variable token error, and can't seem find my way around this.

edited Jan 13 '17 at 15:42

MC Emperor

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asked Jan 13 '17 at 15:29

RileyManda

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var_dump($_POST), check it – LF00 Jan 13 '17 at 15:30
*"I keep getting the undefined variable error"* - for which one? – Funk Forty Niner Jan 13 '17 at 15:31
i dont understand – RileyManda Jan 13 '17 at 15:31
for the variable "token" – RileyManda Jan 13 '17 at 15:31
Oh my "duh", it was in the question's title *lol* – Funk Forty Niner Jan 13 '17 at 15:33
yup.its in the question – RileyManda Jan 13 '17 at 15:34
ok now my question should have been: for which line? You have a few. – Funk Forty Niner Jan 13 '17 at 15:35
line 9 $token =mysqli_real_escape_string($con, $_POST['token']); – RileyManda Jan 13 '17 at 15:38
It means you don't have any `token` variable passed in the POST ones. You should test its existence with `isset($_POST['token'])` before using it. – Veve Jan 13 '17 at 16:06
please elaborate using the code.I dont understand – RileyManda Jan 13 '17 at 19:50
I solved it:i simply set token to empty like this:$token = "";...i declared token before the select all in table query.And it works perfectly.So basically $token = ""; is declared as an empty string to append later. – RileyManda Jan 13 '17 at 19:58

Undefined variable 'token'

0 Answers0