Getting script url from php

Question

I have a PHP file (mymainfile.php)

inside this PHP file, i have include some other PHP files (include.php).

The URL is:

Now i want to get the URL into a variable inside the include.php file.

All my tries with the $_SERVER variables will give me "domain.com/my/include.php" back and that's not what I'm looking for.

Is it possible, and if it's, how?

please provide some code for us to understand the question better — davejal, Jan 18 '17 at 15:21
Here's a similar problem (http://stackoverflow.com/questions/6768793/get-the-full-url-in-php) — YanetP1988, Jan 18 '17 at 15:32
$actual_link = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]"; - that wont solve my problem - like i wrote, the result is not "mymainfile.php" the result is the "include.php" file:..!? — newbieRB, Jan 18 '17 at 15:42
Use `__FILE__` instead. It contains the path of the currently executed PHP context. — , Jan 19 '17 at 02:34
I'm sorry, but __FILE__ gives me the path of the included file, too !? — newbieRB, Jan 19 '17 at 05:23

score 0 · Answer 1 · answered Mar 27 '17 at 12:21

0

Have you tried getcwd()? http://php.net/manual/en/function.getcwd.php Or dirname(__FILE__) (or just __FILE__ ) Aand 1 more try

function get_file_dir() {
    global $argv;
    return realpath($argv[0]);
}

answered Mar 27 '17 at 12:21

1 Answers1