Confusion with ' ints = new int[i]; ' and ' intf = new int; '

Question

int t, i;
cin >> i;

int*s = new int[i];

for (t = 0; t < i; t++) {
    s[t] = t;//How??
    cout << s[t] << "_" << &s[t] << endl;
}

int*f = new int;
*f = t; // Whhhhhy???
delete f;
delete[] s

I declared an array type and an integer as dynamic memory.

While I can assign any ordinary integer value to *f (and pointer value for f), it keeps warning me when assigning an integer value to *s[t].

I have no idea as to why.

Welcome to Stack Overflow! Sounds like you could use a [good C++ book](http://stackoverflow.com/questions/388242/the-definitive-c-book-guide-and-list) — NathanOliver, Jan 18 '17 at 16:20
The *reason* we say you could use one, is because this is a set of problems that really are best answered with a book, since the authors have the time and space to give you an explanation of things like initialization, object lifetime, and management of memory and other resources. — jaggedSpire, Jan 18 '17 at 16:21

score 2 · Accepted Answer · answered Jan 18 '17 at 16:23

2

The reason that you get a warning is because s[t] is shorthand for *(s+t), so *s[t] is shorthand for **(s+t). That's one too many *.

answered Jan 18 '17 at 16:23

MSalters

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Actually that should be error, not warning if compiler would be used properly. – Slava Jan 18 '17 at 20:10
@Slava: The standard merely describes it as a "diagnostic". – MSalters Jan 18 '17 at 21:47

score 0 · Answer 2 · answered Jan 18 '17 at 16:24

0

The [] operator includes an implicit '*'. Assign your value to s[t] rather than *s[t]

answered Jan 18 '17 at 16:24

Dale Wilson

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Confusion with ' int*s = new int[i]; ' and ' int*f = new int; '

2 Answers2

Confusion with ' ints = new int[i]; ' and ' intf = new int; '