Error in sequential execution of pop command and push command?

Question

I used the push command and printed the array before using the pop command, but it is not applied and is gone

var a={
    arr:[],
    boolean:true,
    test:function(){
        if(a.boolean){
            a.arr.push(1);
            console.log(a.arr);
        }
        if(a.boolean)
            a.arr.pop();
    }
}

Possible duplicate of [Is Chrome's JavaScript console lazy about evaluating arrays?](http://stackoverflow.com/questions/4057440/is-chromes-javascript-console-lazy-about-evaluating-arrays) — cartant, Jan 19 '17 at 04:06

score 0 · Answer 1 · answered Jan 19 '17 at 03:59

0

That's because the content of your array is evaluated only after you click the arrow to the left of the array in your console. So what you see in the console in both cases is the result after both push and pop, so they appear empty.

If you hover over the little i symbol to the right of Array[1], it tells you exactly that ("Value below was evaluated just now").

answered Jan 19 '17 at 03:59

Assan

428
1
4
10

It is empty even if it is not assigned to the console. – Sang Yun Jan 19 '17 at 04:12
Why shouldn't it be empty? You are first pushing an item, then popping it. The result is an empty array. – Assan Jan 19 '17 at 04:14

Error in sequential execution of pop command and push command?

1 Answers1