string operations in Python using indexing

Asked Jan 19 '17 at 15:35

Active Jan 19 '17 at 15:36

Viewed 27 times

I have the following piece of code :

str1 = "abcd"
print(str1[1:9:3])

The answer I get is "b"

How is this being calculated. This means that in the string str1, print out the 3rd character from 1st position to 9th. Hence str1[1:9] will be "bcd". And the third character in this should throw me an error. But instead I am getting "b". How is this ?

edited Jan 19 '17 at 15:36

Martijn Pieters

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asked Jan 19 '17 at 15:35

Ricky Mohanty

`3` is not the 3rd character. It is *every third*, starting at the start. `'abcdefg'[1::2]` would give me every second character from `b`, producing `'bdf'`. – Martijn Pieters Jan 19 '17 at 15:37
You might want to check this [answer](http://stackoverflow.com/a/509295/4788274)... – José Sánchez Jan 19 '17 at 15:38

string operations in Python using indexing

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