after succesfully running B.py python returns "python.exe: No module named A.B.py"

Asked Jan 20 '17 at 13:36

Active Jan 20 '17 at 13:38

Viewed 29 times

I have the following folder structure

root_folder\__init__.py #empty file

root_folder\A\__init__.py #emptyfile

root_folder\A\B.py

I am calling from inside root_folder:

root_folder>python -m A.B.py

Correct Python output[everything runs ok until the last line]

C:\Anaconda2\python.exe: No module named A.B.py

My problem is with "python.exe: No module named A.B.py", I'm not sure why it is triggered, since the script executes correctly and how to get read of it.

edited Jan 20 '17 at 13:38

asked Jan 20 '17 at 13:36

twosan

`A.B` is the module name `A.B.py` isn't the file name. Just do `python -m A.B` – Jean-François Fabre Jan 20 '17 at 13:38
I feel stupid now! @Jean-François Fabre thank you, it worked ! – twosan Jan 20 '17 at 13:40
I linked to the original question, great answers here, no need to write another lousy one :) – Jean-François Fabre Jan 20 '17 at 13:51

after succesfully running B.py python returns "python.exe: No module named A.B.py"

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