Regex for finding mp4 in string

Question

I want to get all .mp4 URLs of this String using Regex.

Also I want to know how to get only the last .mp4 URL using Regex.

Thanks

contentType=application/x-mpegURL, url=https://video.twimg.com/amplify_video/822938952332144642/pl/BjHU8aBCbOgZNzXQ.m3u8}, 

Variant{bitrate=0, contentType=application/dash+xml, url=https://video.twimg.com/amplify_video/822938952332144642/pl/BjHU8aBCbOgZNzXQ.mpd}, 

Variant{bitrate=320000, contentType=video/mp4, url=https://video.twimg.com/amplify_video/822938952332144642/vid/320x180/YqZ72rzLj3VWVhy4.mp4}, 

Variant{bitrate=832000, contentType=video/mp4, url=https://video.twimg.com/amplify_video/822938952332144642/vid/640x360/A2vMgzo2ElpPP6TE.mp4}, 

Variant{bitrate=2176000, contentType=video/mp4, url=https://video.twimg.com/amplify_video/822938952332144642/vid/1280x720/j9xbNzRZqEbYs_2s.mp4}]}]";

score 4 · Answer 1 · answered Jan 22 '17 at 20:40

4

Regex:

https?.*?\.mp4

Literal http

Followed by an optional 's': s?

Remove the question mark if they will all use HTTPS.

Followed by as few characters as possible: .*?

Followed by an mp4 extension (literal dot) \.mp4

answered Jan 22 '17 at 20:40

Michael

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*This should be the accepted answer!* However, it would be helpful if you could provide some more information on how to exclude some Strings (like `jpg`) within the URL. i.e. I don’t want to match `` – ixany Oct 01 '18 at 08:56

score 0 · Accepted Answer · edited May 23 '17 at 12:33

2 Approaches:

If you're sure the URL's will always begin with https:// and will not contain a mp4 after the complete URL is finished, then you can use pattern = "https://.*mp4";

String[] arr = {
    "contentType=application/x-mpegURL, url=https://video.twimg.com/amplify_video/822938952332144642/pl/BjHU8aBCbOgZNzXQ.m3u8}",

    "Variant{bitrate=0, contentType=application/dash+xml, url=https://video.twimg.com/amplify_video/822938952332144642/pl/BjHU8aBCbOgZNzXQ.mpd}",

    "Variant{bitrate=320000, contentType=video/mp4, url=https://video.twimg.com/amplify_video/822938952332144642/vid/320x180/YqZ72rzLj3VWVhy4.mp4}",

    "Variant{bitrate=832000, contentType=video/mp4, url=https://video.twimg.com/amplify_video/822938952332144642/vid/640x360/A2vMgzo2ElpPP6TE.mp4}",

    "Variant{bitrate=2176000, contentType=video/mp4, url=https://video.twimg.com/amplify_video/822938952332144642/vid/1280x720/j9xbNzRZqEbYs_2s.mp4}]}]" 
};
String pattern = "https://.*mp4";
Pattern r = Pattern.compile(pattern);

for (String line : arr) {
    Matcher m = r.matcher(line);
    if (m.find()) {
        System.out.println(m.group(0));
    } else {
        System.out.println("NO MATCH");
    }
}

If not, to Support all types of URL's then change your pattern to what is defined here with a little modification,

String pattern = 
    "(((ht|f)tp(s?)\\:\\/\\/|~\\/|\\/)|www.)" + 
    "(\\w+:\\w+@)?(([-\\w]+\\.)+(com|org|net|gov" + 
    "|mil|biz|info|mobi|name|aero|jobs|museum" + 
    "|travel|[a-z]{2}))(:[\\d]{1,5})?" + 
    "(((\\/([-\\w~!$+|.,=]|%[a-f\\d]{2})+)+|\\/)+|\\?|#)?" + 
    "((\\?([-\\w~!$+|.,*:]|%[a-f\\d{2}])+=?" + 
    "([-\\w~!$+|.,*:=]|%[a-f\\d]{2})*)" + 
    "(&(?:[-\\w~!$+|.,*:]|%[a-f\\d{2}])+=?" + 
    "([-\\w~!$+|.,*:=]|%[a-f\\d]{2})*)*)*" + 
    "(#([-\\w~!$+|.,*:=]|%[a-f\\d]{2})*)?\\b"+"mp4";

Output:

NO MATCH
NO MATCH
https://video.twimg.com/amplify_video/822938952332144642/vid/320x180/YqZ72rzLj3VWVhy4.mp4
https://video.twimg.com/amplify_video/822938952332144642/vid/640x360/A2vMgzo2ElpPP6TE.mp4
https://video.twimg.com/amplify_video/822938952332144642/vid/1280x720/j9xbNzRZqEbYs_2s.mp4

The first approache will not work since my urls are in one single line string not in new lines or arrays. but the second approache works perfect thanks — user7453632, Jan 22 '17 at 20:55

Regex for finding mp4 in string

2 Answers2