only printing first if statement python

Question

I did very simple code, I literally just started python but I created some IF and elif statements and it always, prints the first If statement, sorry for bothering people with this petty problem. I tried to search and couldn't find my problem due my lack of experience.

    name = input ("what is your name")
if name == ("x") or ("y"):
    print ("Hello")
elif name == "n" or name == "m" or name ==  "N" or name == "M":
    print  ("a")
else:
    print ("b")

`if name == 'x' or name == 'y'`, better still `if name in ('x', 'y')` — danidee, Jan 23 '17 at 18:28
This might help to understand: https://www.tutorialspoint.com/python/operators_precedence_example.htm — Kyle_S-C, Jan 23 '17 at 18:35

score 0 · Answer 1 · answered Jan 23 '17 at 18:28

0

 if name == "x" or name == "y"

works

answered Jan 23 '17 at 18:28

098799

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Please do not answer duplicates. – juanpa.arrivillaga Jan 23 '17 at 18:30

score 0 · Answer 2 · answered Jan 23 '17 at 18:32

0

your first statement is equivalent to

if (name == 'x') or ('y')

NOT

if (name == 'x') or (name == 'y')

and

if 'y'

is always true

so your code shortcuts and uses the first condition

answered Jan 23 '17 at 18:32

markers

152
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Please do not answer duplicates. – juanpa.arrivillaga Jan 23 '17 at 18:34

only printing first if statement python

2 Answers2