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I have the following:

a <- matrix(c(1, 1, 0, 0, 0, 0, 0, 0, 1, 0, 1, 1, 0, 0), nrow = 2, ncol = 7, byrow = T)

> a
     [,1] [,2] [,3] [,4] [,5] [,6] [,7]
[1,]    1    1    0    0    0    0    0
[2,]    0    1    0    1    1    0    0

When I try to convert a to a vector with:

b <-  split(a, rep(1:nrow(a), each = ncol(a)))

> b
$`1`
[1] 1 0 1 1 0 0 0 # suppose to be 1 1 0 0 0 0 0

$`2`
[1] 1 0 1 0 0 0 0 # suppose to be 0 1 0 1 1 0 0

I did not get the expected output of 1100000 and 0101100. It looked like the vector is filled by column first. How can I do the opposite?

jacky_learns_to_code
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1 Answers1

2

We can split by row

split(a, row(a))

Or use the OP's method

split(a, rep(1:nrow(a), ncol(a)))
#$`1`
#[1] 1 1 0 0 0 0 0

#$`2`
#[1] 0 1 0 1 1 0 0

NOTE: Make sure to not use each, instead use times as matrix, data.frame etc does columnwise split

akrun
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