How to call another dialog using same activity?

Question

[LuisIntent("test-intent")]
        public async Task test(IDialogContext context, IAwaitable<IMessageActivity> argument, LuisResult result)
        {
            await Conversation.SendAsync(context.MakeMessage(), () => SimpleFacebookAuthDialog.dialog);
        }

I tried this. But the problem occurs when i try to send simple string message

await context.PostAsync("msg");

from SimpleFacebookAuthDialog. It throws an exception

The data is changed.

context.MakeMessage() and Activity are not the same.

Some help ?

score 1 · Accepted Answer · edited May 23 '17 at 11:52

1

Try using context.Call or context.Forward which are the ways to launch child dialogs instead of

 await Conversation.SendAsync(context.MakeMessage(), () => SimpleFacebookAuthDialog.dialog);

Check this and the MultiDialogs sample for more information.

If you want to pass the same activity, then probably context.Forward is the way to go.

edited May 23 '17 at 11:52

Community

1
1

answered Jan 25 '17 at 10:02

Ezequiel Jadib

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Please accept and upvote if it was useful. I provided some piece of advice on the other thread in GitHub (https://github.com/Microsoft/BotBuilder/issues/2110#issuecomment-275075947). Try moving the logic to a new dialog. But first try to read about al the core concepts involved. – Ezequiel Jadib Jan 25 '17 at 10:56

How to call another dialog using same activity?

1 Answers1