php preg_match_all for specific value

Question

I have a html content which has a URL fragment looks like following:

<a href="#/news/0294928/what-a-great-idea">

What I need to do is just to grab the number followed by #/news/

Any good idea? I tried following, but it gets only 4 results for me

preg_match_all('/<a href="#\/news\/(.+)\/?\"?>/i', $html_cont, $matches );

Please help me, Thanks.

First you extract the href attribute using XPath, then you explode the result with `/` and you take the item number 2. — Casimir et Hippolyte, Jan 26 '17 at 19:18
Grab using javascript's window.location.href and then split on the /. From there it's the third item in the resulting array. — Raydot, Jan 26 '17 at 19:19
Do not parse HTML with regular expressions. Use [the proper tools](http://php.net/domdocument). — miken32, Jan 26 '17 at 19:22

score 0 · Answer 1 · answered Jan 26 '17 at 19:25

0

The detail of my comment:

$dom = new DOMDocument;
libxml_use_internal_errors(true);
$dom->loadHTML($yourHTML);

$xp = new DOMXPath($dom);
$hrefNodeList = $xp->query('//a/@href[starts-with(., "#/news/")]');

foreach ($hrefNodeList as $hrefNode) {
    echo explode('/', $hrefNode->nodeValue)[2] . PHP_EOL;
}

answered Jan 26 '17 at 19:25

Casimir et Hippolyte

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any idea with preg_match_all() ? – Wilson Breiner Jan 26 '17 at 19:27
@WilsonBreiner: a precise idea if you want to know, but I avoid shitty code. – Casimir et Hippolyte Jan 26 '17 at 19:28

score 0 · Accepted Answer · answered Jan 26 '17 at 19:27

0

$string = '<a href="#/news/0294928/what-a-great-idea">';
preg_match_all("/#\/news\/(.*?)\//",$string, $m);
echo '<pre>'.print_r($m[1]).'</pre>';

so in $m[1] are all your numbers if thats what ure lookin for?

answered Jan 26 '17 at 19:27

Donny Doe

46
7

Oh. WHAT A GREAT !!! – Wilson Breiner Jan 26 '17 at 19:29

php preg_match_all for specific value

2 Answers2