(See this question for what the m means)
I need to construct the include path of .virtualenvs/foo/include/pythonX.Ym to compile something (i.e. -I...) against the virtualenv. I can get the X.Y using sys.version or sys.final_version.
How do I get the m to construct the include path?
EDIT: I tried sys.executable but that is pointing to .../foo/bin/python, which is unhelpful for this.
The easiest way to get the include path is to use the sysconfig.get_path() function:
import sysconfig
include_path = sysconfig.get_path('include')
This path is adjusted for virtualenvs already. For scripting purposes outside of Python, you can either print the path directly:
$ python -c 'import sysconfig; print(sysconfig.get_path("include"))'
or get all sysconfig data by running the module as a script:
$ python -m sysconfig
then parse the output that dumps to stdout.
Other than that, if you only want the executable name (with the m included), you can get that from the sys.executable variable; this includes the m suffix:
>>> import sys
>>> sys.executable
'/usr/bin/python3.5m'
As of Python 3.2, you can also use the sys.abiflags variable; it is set to m in this case:
>>> sys.abiflags
'm'
Also see PEP 3149.
For earlier Python versions, the various flags that influence the suffixes are available still via the aforementioned sysconfig module as configuration variables:
pymalloc = bool(sysconfig.get_config_var('WITH_PYMALLOC'))
pydebug = bool(sysconfig.get_config_var('WITH_PYDEBUG'))
wideunicode = bool(sysconfig.get_config_var('WITH_WIDE_UNICODE'))
Note that ubuntu merely compiles multiple binaries and adjusts the executable name to reflect the configuration option chosen; on other systems the ABI flags are not necessarily reflected in the executable name.
