Syntax error in bash script : Invalid Arithmetic Operator in sed command

Asked Jan 28 '17 at 12:26

Active Jan 29 '17 at 02:46

Viewed 46 times

Script:

#!/bin/bash

line_num=349

pattern_2="$(sed -n "${line_num}p" ssg_ds_5%.csv | awk 'BEGIN {FS= ","}; {print $9}')"

echo "$pattern_2"

Error:

")syntax error: invalid arithmetic operator (error token is "209
'ed: -e expression #1, char 4: unknown command: `

The sed command is supposed to run in a loop and extract one line from a csv file. It works fine when I give the command from the terminal, but when I run the script, I receive this error.

Any help will be greatly appreciated. TIA

edited Jan 29 '17 at 02:46

asked Jan 28 '17 at 12:26

Shafquat

You should remove the wrapping double quotes in the main line -- they are not needed. – Jdamian Jan 28 '17 at 12:40
The error message seems messy, are Windows end-of-lines involved? – choroba Jan 28 '17 at 12:57
Try `"$(tr '\r' '\n' – Walter A Jan 28 '17 at 16:56
Yes, there were end of lines involved `^M` present in the data. Missed those somehow. Thanks a lot. I added the `-d` option to `tr`: `"$(tr -d '\r' '\n' < ssg_ds_5%.csv | sed -n "${line_num}p" |...` – Shafquat Jan 29 '17 at 03:15

Syntax error in bash script : Invalid Arithmetic Operator in sed command

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