Python: convert string of multiple hexadecimal values to integer

Question

I am having string of four hex numbers like:

"0x00 0x01 0x13 0x00"

which is equivalent to 0x00011300. How i can convert this hex value to integer?

Possible duplicate of [How to get hex string from signed integer](http://stackoverflow.com/questions/228702/how-to-get-hex-string-from-signed-integer) — Danieboy, Jan 31 '17 at 14:15

Moinuddin Quadri · Accepted Answer · 2017-01-31T14:32:48.503

3

Since you are having string of hex values. You may remove ' 0x' from the string to get the single hex number string. For example:

my_str =  "0x00 0x01 0x13 0x00"
hex_str = my_str.replace(' 0x', '')

where value hold by hex_str will be:

'0x00011300'   # `hex` string

Now you may convert hex string to int as:

>>> int(hex_str, 16)
70400

edited Jan 31 '17 at 14:32

answered Jan 31 '17 at 14:19

Moinuddin Quadri

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score 1 · Answer 2 · answered Jan 31 '17 at 14:22

1

>>> s="0x00 0x01 0x13 0x00"
>>> a=0
>>> for b in s.split():
...    a = a*256 + int(b,16)
... 
>>> a
70400
>>> hex(a)
'0x11300'

answered Jan 31 '17 at 14:22

stark

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score 0 · Answer 3 · edited May 23 '17 at 10:29

The answer is here Convert hex string to int in Python.

Without the 0x prefix, you need to specify the base explicitly, otherwise there's no way to tell:

x = int("deadbeef", 16)

With the 0x prefix, Python can distinguish hex and decimal automatically.

print int("0xdeadbeef", 0)
3735928559

print int("10", 0)
10

(You must specify 0 as the base in order to invoke this prefix-guessing behavior; omitting the second parameter means to assume base-10. See the comments for more details.)

Python: convert string of multiple hexadecimal values to integer

3 Answers3