convert NSString to long value

Asked Jan 31 '17 at 15:38

Active Jan 31 '17 at 15:40

Viewed 360 times

Converting NSString to long value not showing proper data.

@"86200054340607012013" integerValue or intValue showing - 2147483647

@"86200054340607012013" longlongvalue showing - 9223372036854775807

NSNumberFormatter * f = [[NSNumberFormatter alloc] init];
[f setNumberStyle:NSNumberFormatterDecimalStyle];
NSNumber * myNumber = [f numberFromString:@"86200054340607012013"];

showing - 9223372036854775808

 NSNumberFormatter* formatter = [[NSNumberFormatter alloc] init];
 NSLog(@"======>%lu", [[formatter numberFromString:@"86200054340607012013"] unsignedLongValue]);

showing - 12413078045768810496

What is the proper way to converting this

edited Jan 31 '17 at 15:40

asked Jan 31 '17 at 15:38

Santanu Das Adhikary

@Napolux Have already gave the code and output value. It's not working – Santanu Das Adhikary Jan 31 '17 at 15:41
Use `NSDecimalNumber`. – rmaddy Jan 31 '17 at 15:42
Your number is simply too big to fit in an `int` (32 bits) or a `long long` (64 bits): 86200054340607012013 ≈ 2^66.2. As @rmaddy mentions, you need to use something which can store a number that large (e.g. `NSDecimalNumber`) – Itai Ferber Jan 31 '17 at 15:54
You can't use integral type because max size of standard type is 8 bytes, but your number has 9 bytes. – Sergey Jan 31 '17 at 15:57

convert NSString to long value

0 Answers0