php JSON_encode not working

Question

I want to get this JSON output from this . unfortunately json_encode() function won't encode array into that format. It's nothing returning at all. here is my code.`

$output = array(
    'responseData' => array(),
    'responseDetails' => null,
    'responseStatus' => 200
);

$x = 0;
while ($row = mysqli_fetch_assoc($result)) {
    foreach ($row as $k => $v) {
        $output['responseData']['result'][$x][$k] = $v;
    }
    $x++;
}

print_r($output);
header('Content-Type: application/json');
echo json_encode($output , JSON_FORCE_OBJECT);

I can't find the reason. someone please help me find the solution.

Edit : Sorry. Here is outputs -

Expected JSON output -

{
"responseData": {
    "results": [{
        "qid": 1,
        "qtitle": "When do we finish this project ?",
        "qimage_url": "http://www.wearesliit.com/example.png",
        "user": "samith",
        "date": "2016-01-01T02:15:12.356Z",
        "type": 1,
        "category": 5,
        "tags": ["common_senese", "truth", "bazsa_awsanna"],
        "note": "Sample quetion"
    }, {}, {}]
},
"responseDetails": null,
"responseStatus": 200 }

I don't get any JSON output at all. but here is the print_r result of the array.

 Array(
[responseData] => Array
    (
        [result] => Array
            (
                [0] => Array
                    (
                        [question_ID] => 1
                        [question_Title] => Which shape does not belong with the other three shapes?
                        [question_Image_URL] => http://www.wearesliit.com/images/quiz/questions/1.jpg
                        [quetion_Note] => Easy IQ question.
                        [category_ID] => 7
                        [username] => samith
                        [added] => 2017-01-29 21:50:52
                    )

                [1] => Array
                    (
                        [question_ID] => 2
                        [question_Title] => Tim earns $10 per hour at his job.  When he gets paid on Friday, he is paid for 40 hours of work.  He then goes out and spends 10% of his earnings on entertainment that weekend.  How much money is he left with on Monday?
                        [question_Image_URL] => 
                        [quetion_Note] => Easy IQ question.
                        [category_ID] => 7
                        [username] => samith
                        [added] => 2017-01-29 21:50:52
                    )
            )

    )

[responseDetails] => 
[responseStatus] => 200 )

Answer 1

Thanks to @awiebe I found the exact error. It's

Malformed UTF-8 characters, possibly incorrectly encoded

Thank you all, I found a solution from an another question. 'Malformed UTF-8 characters, possibly incorrectly encoded' in Laravel

Answer 2

json_encode() function returns "false" when the encode fails and a "false" result does not appear in an echo or print. See: http://php.net/manual/en/function.json-encode.php The best way to handle such problems would be using the json_last_error_msg() method and performing an action according to the found error. See: http://php.net/manual/en/function.json-last-error-msg.php. An example would be:

$show_json = json_encode($output , JSON_FORCE_OBJECT);
if ( json_last_error_msg()=="Malformed UTF-8 characters, possibly incorrectly encoded" ) {
    $show_json = json_encode($API_array, JSON_PARTIAL_OUTPUT_ON_ERROR );
}
if ( $show_json !== false ) {
    echo($show_json);
} else {
    die("json_encode fail: " . json_last_error_msg());
}

The thing is, if the problem was an encoding character, it will no be shown. Just hope that character is not essential for your work or if you can find the mismatch input in a zigazillion string list, correct it. Other types of errors can be found here: http://php.net/manual/en/json.constants.php. Just apply the if statement and correction for the error you find.

I hope this helps someone.

Answer 3

I would like to refer you about this issue, on link I suggest you use a json_encode wrapper like this :

function safe_json_encode($value){
if (version_compare(PHP_VERSION, '5.4.0') >= 0) {
    $encoded = json_encode($value, JSON_PRETTY_PRINT);
} else {
    $encoded = json_encode($value);
}
switch (json_last_error()) {
    case JSON_ERROR_NONE:
        return $encoded;
    case JSON_ERROR_DEPTH:
        return 'Maximum stack depth exceeded'; // or trigger_error() or throw new Exception()
    case JSON_ERROR_STATE_MISMATCH:
        return 'Underflow or the modes mismatch'; // or trigger_error() or throw new Exception()
    case JSON_ERROR_CTRL_CHAR:
        return 'Unexpected control character found';
    case JSON_ERROR_SYNTAX:
        return 'Syntax error, malformed JSON'; // or trigger_error() or throw new Exception()
    case JSON_ERROR_UTF8:
        $clean = utf8ize($value);
        return safe_json_encode($clean);
    default:
        return 'Unknown error'; // or trigger_error() or throw new 
Exception();
}
}


function utf8ize($mixed) {
if (is_array($mixed)) {
    foreach ($mixed as $key => $value) {
        $mixed[$key] = utf8ize($value);
    }
} else if (is_string ($mixed)) {
    return utf8_encode($mixed);
}
return $mixed;
}

And after define these function you can use it direct,

echo safe_json_encode($response);

Answer 4

remove

header('Content-Type: application/json');

Remember that header() must be called before any actual output is sent, either by normal HTML tags, blank lines in a file, or from PHP. It is a very common error to read code with include, or require, functions, or another file access function, and have spaces or empty lines that are output before header() is called. The same problem exists when using a single PHP/HTML file.

and JSON_FORCE_OBJECT from

echo json_encode($output , JSON_FORCE_OBJECT);