Type 'Any' has no subscript memebers

Question

When i converted to swift 3 , its saying type any has no subscript memebers.

let dataDictionary = try JSONSerialization.jsonObject(with: data!, options: JSONSerialization.ReadingOptions.mutableContainers)
let accessToken = dataDictionary["access_token"] as! AnyObject?

Ihave tried many possiblities but didn't worked.

Is none of this works for you http://stackoverflow.com/search?q=%5Bswift3%5DType+%27Any%27+has+no+subscript+members ? or this http://stackoverflow.com/search?q=Type+%27Any%27+has+no+subscript+members ? — Nirav D, Feb 03 '17 at 06:46
@user2702179 You need to specify the type of `dataDictionary` to compiler. like `if let result = dataDictionary as? [String:Any]` then use subscript with result. — Nirav D, Feb 03 '17 at 06:48
@user2702179 Initialize dataDictionry this way `if let dataDictionary = (try? JSONSerialization.jsonObject(with: data!, options: [])) as? [String:Any] { let accessToken = dataDictionary["access_token"] as? String } ` — Nirav D, Feb 03 '17 at 06:52

score 0 · Answer 1 · answered Feb 03 '17 at 06:52

The return type of JSONSerialization.jsonObject(with:options:) is Any which doesn't allow subscripting. You have to use explicit type conversion to subscript. If you're trying to cast the data to [String: Any] you could do the following:

if let dataDictionary = dataDictionary as? [String: Any] {
    // dataDictionary["access_token"] as AnyObject
}

score 0 · Answer 2 · answered Feb 03 '17 at 06:54

JSONSerialization.jsonObject throws an error so let catch it in a do catch block

    do {
        let dataDictionary = try JSONSerialization.jsonObject(with: data!, options: JSONSerialization.ReadingOptions.mutableContainers) as! [String: Any]
        let accessToken = dataDictionary["access_token"] as! AnyObject
    } catch let error as NSError {
        print(error)
    }

Type 'Any' has no subscript memebers

2 Answers2