URL GET request with parameters

Question

For example I have this string:

String url = "http://lookup.dbpedia.org/api/search.asmx/KeywordSearch?username=USERNAME&password=PASSWORD";

and I have the String USERNAME="123456" and String PASSWORD="123"; When I make the URL GET request how do I inject the USERNAME and PASSWORD into the URL?

Looks like you formed the correct URL. What issue or problem you are facing? Describe more. — GrabNewTech, Feb 03 '17 at 08:06
I have a webservice with XML response, to get access to the response I need to pass a username and a password. I don't not know how to give a reference of the user and password to the url string. I mean how to inject the content of the user and pass strings into the url String. — Dan NoNeed, Feb 03 '17 at 08:14
Have you learned about string concatenation? Why do you have the username and password in your URL string and not put them there when you actually make the request? — OneCricketeer, Feb 03 '17 at 08:16

Jeroen VL · Answer 1 · 2017-02-03T08:16:24.370

0

You can just use the Replace function.

This will give you the following code:

String url = "http://lookup.dbpedia.org/api/search.asmx/KeywordSearch?username=USERNAME&password=PASSWORD";
String USERNAME="123456";
String PASSWORD="123";

url = url.replace("?username=USERNAME&password=PASSWORD","username="+USERNAME+"&password="+PASSWORD);

Although it doesn't seem wise to send a Username and Password in the querystring! If no other option is available be sure to use https so this is not visible for sniffing tools. Otherwise use the default authentication.

edited Feb 03 '17 at 08:16

answered Feb 03 '17 at 08:12

Jeroen VL

341
5
9

Why would you do that? Android has URI builder class specifically for this – OneCricketeer Feb 03 '17 at 08:14
If he starts with this full string you will have to cut it first at the '?' so you can use the builder to add the querystring parameters. A String function is always needed. Then it seems shorter to just replace it? – Jeroen VL Feb 03 '17 at 08:19
You'd leave off the question mark for the builder. It adds it. Surely you'd recall whatever method again for different usernames and passwords, so not sure about shorter – OneCricketeer Feb 03 '17 at 08:22

score 0 · Answer 2 · answered Feb 03 '17 at 08:15

0

You can create a method like below

public String getUrl(String Username,String Password){
    String url = "http://lookup.dbpedia.org/api/search.asmx/KeywordSearch?username="+Username+"&password="+Password;
    return url;
}

After that you can call this method

String URL = getUrl("Username","Password");

answered Feb 03 '17 at 08:15

Narendra Motwani

1,085
10
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Thanks, that is what I wanted! – Dan NoNeed Feb 03 '17 at 08:18
Your Welcome If this help you then can you please accept my answer – Narendra Motwani Feb 03 '17 at 08:40

URL GET request with parameters

2 Answers2