how to order charters of a descending order? if similar apathetically. frequency first then alphabetical series .
#!/user/bin/python3
# -*- coding: utf-8 -*-
import string
text = """
Mississippi
"""
# create a character: frequency dictionary
charFreqDic = {}
for char in text.upper():
charFreqDic[char] = charFreqDic.get(char, 0) + 1
print ("Characters sorted by ASCII number:")
# create a sorted list of keys
key_list = sorted(charFreqDic.keys())
for key in key_list:
# don't show space and newline
if key not in " \n":
# associate the value with the key
print ("%2s %3d" % (key, charFreqDic[key]))
print ("Characters sorted by frequency:")
print("\n")
print("No Occur"+"\t "+ "Character")
# convert charFreqDic to list of (k, v) tuples with charFreqDic.items()
# flip tuple elements to (v, k) using list comprehension
# then sort list of tuples (order is v,k), highest v first
#dictionary to list
copytolist=[]
for K,V in charFreqDic.items():
copytolist.append((V,K));
copytolist=sorted(copytolist,reverse=True)
print(copytolist)
print("Words sorted by frequency:")
print("\n")
print("No Occur" + "\t " + "Word")
for K in copytolist:
if K[1] not in " \n":
print(str(K[0]) + "\t\t\t " + str(K[1]) + "'s")
output is Words sorted by frequency:
No Occur Word
4 S's
4 I's
2 P's
1 M's
But I wanted the output to be ordered both based on frequency and based on alphabetical series if frequency is similar.
No Occur Word
4 I's
4 S's
2 P's
1 M's
