pop current view twice from navigation

Question

I have four pages in hierarchy, 0 -> 1 -> 2 -> 3 and I am navigating to them with this.router.navigate(..).

Is there a way, how to get from view (3) directly to view (1)? Calling this.location.back(); twice shows for while page (2), which I do not want to.

Can I pop it directly or navigate to page (1) while keeping (0) still on stack?

Edit: I need to be it working primary on Android/iOS.

Thanks a lot.

score 2 · Answer 1 · answered Feb 03 '17 at 14:12

2

Perhaps the skipLocationChange parameter of routerLink or NavigationExtras does what you want.

this.router.navigate('some route', 
    { navigationExtras: { skipLocationChange: true}})

This way the navigation from 1 to 2 or 2 to 3 doesn't add a history entry and navigating back from 3 directly results in going back to 1.

answered Feb 03 '17 at 14:12

Günter Zöchbauer

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Unfortunately, I need to keep 2 on stack for case of returnin there from another page e.g. 2 -> 4. – Ondrej Feb 03 '17 at 15:58
1

Don't see a way to accomplish that. – Günter Zöchbauer Feb 03 '17 at 16:00
TY, knowing that st. is not possible is answer too. – Ondrej Feb 03 '17 at 16:13
Perhaps listening for back navigation and then navigate back again by code http://stackoverflow.com/questions/25806608/how-to-detect-browser-back-button-event-cross-browser – Günter Zöchbauer Feb 03 '17 at 16:43
I don't think this answer will work for NativeScript routes. – Otacilio Oliveira Oct 10 '17 at 19:25
@OtacilioOliveiraLimaNeto any reason why? I don't know NativeScript. – Günter Zöchbauer Oct 10 '17 at 19:25
I think `skipLocationChange` is not supported on NativeScript routing yet. – Otacilio Oliveira Oct 10 '17 at 20:16

pop current view twice from navigation

1 Answers1