How to print all elements of a list with trailing zeroes in python

Asked Feb 04 '17 at 13:00

Active Feb 06 '17 at 12:23

Viewed 46 times

I am very new to programming and started learning my first programming language in python.

My code:

a=[0001,0052,1122,0127]

for i in a:
        nums = '{:05}'.format(i)
        print(nums)

Output :

Expected Output:

I am not getting what is wrong here.

Someone had closed the question but I am getting how can I do this? I tried this also,but not working. please help

for i in a:
        nums = '{:05}'.format(int(i, 8))
        print(nums)

edited Feb 06 '17 at 12:23

Alfro

asked Feb 04 '17 at 13:00

1

Numbers that start with `0` are interpreted as octal, not decimal. – Barmar Feb 04 '17 at 13:01
`52` octal is `42` decimal. – Barmar Feb 04 '17 at 13:02
Just remove the trailing zeros in your list. You should have `[1, 52, 1122, 127]`. See [this answer](http://stackoverflow.com/a/13431333/4257747) on the duplicated question. – Alfro Feb 06 '17 at 11:51

0 Answers0