How do I divide 2 floats in Swift?

Asked Feb 04 '17 at 22:20

Active Feb 04 '17 at 22:38

Viewed 67 times

I'm getting the errors

Col 60: binary operator '/' cannot be applied to two 'Float' operands

Expected an argument list of type '(Double, Double)' (line 62, col 60)

I don't see why I cannot divide the two numbers. I'm working on a project that requires me to run these calculations using single precision values, so I need to use Float here.

The code:

func logC(val: Double, forBase base: Double) -> Float {
    return Float(log(val)/log(base))
}

logC(val: abs((sum1(N: 12100)-sum3(N: 12100))/sum3(N: 12100) ), forBase: 10)

What I've tried:

Casting the result to Float
Casting each parameter in the calculation to Float

edited Feb 04 '17 at 22:38

asked Feb 04 '17 at 22:20

loltospoon

It's also a dupe of [many other questions](http://stackoverflow.com/search?q=%5Bswift%5D+binary+operator+cannot+be+applied+to+two+operands). Please always search on an error before posting. – rmaddy Feb 04 '17 at 22:22
That question didn't help and searching through other questions didn't either. – loltospoon Feb 04 '17 at 22:27
Then you didn't actually read and understand my answer to the duplicate. It's the same basic problem. – rmaddy Feb 04 '17 at 22:30
You want the result to be a Double so the two operands must also be two Doubles. – rmaddy Feb 04 '17 at 22:31
I do not want the results to be a Double. – loltospoon Feb 04 '17 at 22:32
The goal here is to write a program using single precision values in order to learn more about them. I do not want int or double values. – loltospoon Feb 04 '17 at 22:33
Then why is the return type of your function Double? – rmaddy Feb 04 '17 at 22:34
Oh, that's a mistake. I'll update. – loltospoon Feb 04 '17 at 22:38
You still have a mix of types. Why are the parameters of type `Double` if you want `Float`? – rmaddy Feb 04 '17 at 22:53
Ah, that was it. Thanks! – loltospoon Feb 04 '17 at 23:04

How do I divide 2 floats in Swift?

0 Answers0