Regex: How to find a GUID in a long string?

Question

Let's say I have this string:

str = 'something-rows-1973912739821738172-25892e17-80f6-415f-9c65-7395632f0223'

I need to remove GUID part:

25892e17-80f6-415f-9c65-7395632f0223

This is what I've so far but it isn't working:

c = re.compile('[0-9a-f]{12}4[0-9a-f]{3}[89ab][0-9a-f]{15}\Z', re.I)
res = c.match(str)
print(res)

Can anyone please help?

str[:-37] is really neat! but the format of my input string may change in future so i need to be able to identify a GUID when there is lots of text surrounding it. — 90abyss, Feb 05 '17 at 02:44

score 28 · Accepted Answer · edited May 23 '17 at 12:33

28

From this answer, you need this:

[0-9a-f]{8}-[0-9a-f]{4}-[1-5][0-9a-f]{3}-[89ab][0-9a-f]{3}-[0-9a-f]{12}

edited May 23 '17 at 12:33

Community

answered Feb 05 '17 at 02:45

To be clear, this answer is the one which **doesn't** match NIL UUID, `00000000-0000-0000-0000-000000000000`. Of course, the answer referenced also includes a regex which will match NIL and non-NIL. – Tyler Montney Aug 23 '23 at 19:52

1 Answers1