Python failing to recognise number above 1000

Question

magicnumber = 2000 ;

for x in range(10000):
    if x is magicnumber:
        print(x,"Is the Magic Number")
        break

I need assistance.

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score 4 · Answer 1 · edited May 23 '17 at 12:01

4

You need to replace is with ==. And you need to read this for more understanding: Is there a difference between `==` and `is` in Python?

magicnumber = 2000 ;

for x in range(10000):
    if x == magicnumber:
        print(x,"Is the Magic Number")
        break

Output:

(2000, 'Is the Magic Number')

edited May 23 '17 at 12:01

Community

answered Feb 05 '17 at 09:03

Mohammad Yusuf

score 1 · Answer 2 · answered Feb 05 '17 at 09:04

1

if x is magicnumber:

is the same as

if x is 2000:

which returns false, therefore that condition is never met

if x == magicnumber:

is what you are looking for...

answered Feb 05 '17 at 09:04

score 1 · Answer 3 · edited Feb 05 '17 at 11:55

1

magicnumber = 2000

for x in range(10000):
    if x == magicnumber:
        print(x,"Is the Magic Number")
        break

edited Feb 05 '17 at 11:55

Mohammad Yusuf

answered Feb 05 '17 at 09:04

Vikrant

3 Answers3