Codename One Parse Json

Question

I can't seem to figure out how to parse this Json in Codename One:

{
  "ParsedResults": [
    {
      "TextOverlay": {
        "Lines": [],
        "HasOverlay": false,
        "Message": "Text overlay is not provided as it is not requested"
      },
      "FileParseExitCode": 1,
      "ParsedText": "REPORT 1 - STUDENT INFORMATION SERIES \r\n50 SOMEWHERE SCHOOL DISTRICT COUNTY SCHOOLS \r\n1234 SOMEWHERE SCHOOL \r\nDATE: 01/01/0001 \r\nCLASS ROLE \r\nBLDG-RM \r\n01-111 \r\nPGM \r\n101 \r\nMINS \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n090 \r\n10 \r\nFM \r\n2 \r\nMINS \r\n090 \r\nPGRM \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n101 \r\n11 \r\nFW \r\n3 \r\nTEACHER \r\n100 SMITH, C \r\nDATES \r\nCOURSE SEC/M \r\n1000111 \r\nDAYS \r\nMTWRF \r\nSTUDENT NAME \r\nADOE, AYANA \r\nBEDOE, BROOKE \r\nTITLE \r\nSOC ST \r\nTIMES \r\nSCHL \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n4207 \r\n08 \r\nFH \r\n3 \r\nT \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n3 \r\n09 \r\no \r\n0900 1100 080117 060118 \r\nSTDT NBR \r\n123456789 \r\n234567891 \r\n345678912 \r\n456789123 \r\n567891234 \r\n678912345 \r\n789123456 \r\n891234567 \r\n912345678 \r\n012345678 \r\n123456780 \r\n234567801 \r\n345678012 \r\n456780123 \r\n567801234 \r\n678012345 \r\n780123456 \r\n801234567 \r\n123321123 \r\n234432234 \r\n456654456 \r\n567765567 \r\n678876678 \r\n789987789 \r\n890098890 \r\n901109901 \r\nSR \r\nFM \r\nFW \r\nMB \r\nMM \r\nMH \r\nFW \r\nMA \r\nFW \r\nMl \r\nMW \r\nFM \r\nMB \r\nMH \r\nMB \r\nFM \r\nMM \r\nMB \r\nMM \r\n06 \r\n2 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n05 \r\n07 \r\n2 \r\nCODOE, CHRISTOPHER \r\nDOE, DEREK \r\nEDOE, EDWARD \r\nFEDOE, FERLICIA \r\nGODOE, GINA \r\nHEDEO, HENRY \r\nINDEO, INDIA \r\nJADOE, JERRELL \r\nKIDOE, KARL \r\nLADOE, LYSHA \r\nMEDOE, MADAIYCA \r\nNIDOE, NEPHTALIE \r\nOODOE, OLIVIA \r\nPELDOE, PATRICK \r\nQUODOE, QUINTAN \r\nRUDOE, RACHEL \r\nSTADOE, STEPHAN \r\nTEEDOE, TERRELL \r\nUEDOE, UMMI \r\nVEDOE, VALERIA \r\nWADOE, WAHEED \r\nXADOE, XIE QIAN \r\nYIDOE, YADLEY \r\nZIADOE, ZANDER \r\n03 \r\nMl \r\n1 \r\nOK \r\nMA \r\n1 \r\n01 \r\nMB \r\n4 \r\n02 \r\nMH \r\n2 \r\n04 \r\nMM \r\n2 \r\n05 \r\n26 \r\nMW \r\n2 \r\n",
      "ErrorMessage": "",
      "ErrorDetails": ""
    }
  ],
  "OCRExitCode": 1,
  "IsErroredOnProcessing": false,
  "ErrorMessage": null,
  "ErrorDetails": null,
  "ProcessingTimeInMilliseconds": "8550"
}

I want the ParsedText portion. Any help would be appreciated.

It's not since the JSON parsing in Codename One is different — Shai Almog, Feb 07 '17 at 08:37
@cricket_007 please re-read the question/answer and reopen it. You will notice that the answer is **different** from the one that's "supposedly" a duplicate. — Shai Almog, Feb 08 '17 at 07:23

score 0 · Answer 1 · answered Feb 06 '17 at 06:19

0

With the JSONParser this should be something like:

JSONParser p = new JSONParser();
Map<String, Object> m = p.parseJSON(myReader);

List l = (List)m.get("ParsedResults");
Map<String, Object> r1 = (Map<String, Object>)l.get(0);
String parsedText = (String)r1.get("ParsedText");

answered Feb 06 '17 at 06:19

Shai Almog

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Thanks Shai, I'll give this a shot. – Sonic Motion Feb 06 '17 at 15:55
I'm sure I'm doing something wrong with this, but its giving me an error on this line of code: Map r1 = (Map)l.get(0); error: cannot find symbol symbol: method get(int) – Sonic Motion Feb 07 '17 at 00:01
Why raw `List`? – OneCricketeer Feb 07 '17 at 05:51
You can use a list of `Map` but since you will need a cast anyway I'd rather go with raw which isn't as verbose – Shai Almog Feb 07 '17 at 08:36

score 0 · Answer 2 · answered Feb 07 '17 at 05:43

Had to make it an ArrayList, thanks for pointing me in the right direction.

JSONParser p = new JSONParser();
Map<String, Object> m = p.parseJSON(myReader);

ArrayList l = (ArrayList)m.get("ParsedResults");
Map<String, Object> r1 = (Map<String, Object>)l.get(0);
String parsedText = (String)r1.get("ParsedText");

Codename One Parse Json

2 Answers2