How to add jquery variable data in php statement?

Question

i am getting stuck on this problem. i want to do using jquery

window.newdatevalue = '<?php echo date("Y-m-d") ?>';// this date is dynamic

var newdate = window.newdatevalue;

console.log(newdate); // when i print this it give me right result -2017-02-06 

var finaldate = "<?php echo date('d/M/y',strtotime('"+newdate+"'))?>";

console.log(finaldate); // but when i print this it give me wrong result 01/Jan/70

Can anyone help me what i am doing wrong

try change finaldate format to "Y-m-d" [ echo date("Y-m-d",strtotime('"+newdate+"')) ] — SarangaR, Feb 06 '17 at 05:27
PHP executes on the server, then the server sends the page to the browser, and javascript runs. You can't just inject a javascript variable in PHP, it's too late — adeneo, Feb 06 '17 at 05:30
for change date format see http://stackoverflow.com/questions/33299687/how-to-convert-dd-mm-yyyy-string-into-javascript-date-object — Bharat Dangar, Feb 06 '17 at 05:37
I think, you are misunderstanding some principle of server side programming any way I think you hope following answer [ echo date("d/m/Y",strtotime(date('Y-m-d'))); ] or [ echo date('d/m/Y'); ] — SarangaR, Feb 06 '17 at 05:38

score 0 · Answer 1 · answered Feb 06 '17 at 05:30

0

Can try this. It might help you.

window.newdatevalue = '<?php echo date("d-m-Y", strtotime(date("Y-m-d"))); ?>'

console.log(window.newdatevalue);

answered Feb 06 '17 at 05:30

Naincy

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where is $originalDate; – kunal Feb 06 '17 at 05:31
updated my answer – Naincy Feb 06 '17 at 05:31
i have different date in different day. So i want to place variable in strtotime – kunal Feb 06 '17 at 05:32
what you mean in above... please specify more clearly – Naincy Feb 06 '17 at 05:34

How to add jquery variable data in php statement?

1 Answers1