How to modify a boolean field model in Django?

Question

I'm trying to apply an activate/deactivate feature for my posts on a blog app. Here is my model. My desire is to be able to activate the post to show it in a template but how can I change (set) the value of is_activate field through the view.py? Here is my model:

class Post(models.Model):
   title = models.CharField(max_length=250)
   slug = models.SlugField(max_length=250)
   body = models.TextField()
   is_activate = models.BooleanField(default=False)

Summarizing: I need a button which on clicking activates a post and then show it in a template with other activated posts.

What's complicated here? Why is changing the `is_activate` field any different from changing any other fields? — Daniel Roseman, Feb 07 '17 at 11:57
@EvansMurithi beacause I need to use a buttom in a template and not through the admin — Italo Lemos, Feb 07 '17 at 12:06
@DanielRoseman Well, some tutorial only show how to retrieve from the database and not how to set a variable — Italo Lemos, Feb 07 '17 at 12:08
No good ones do that. The official one certainly doesn't. But even if they did, can you not work it out? — Daniel Roseman, Feb 07 '17 at 12:09
Does this answer your question? [How to update fields in a model without creating a new record in django?](https://stackoverflow.com/questions/3681627/how-to-update-fields-in-a-model-without-creating-a-new-record-in-django) — Abdul Aziz Barkat, Jul 18 '22 at 11:54

score 2 · Accepted Answer · answered Feb 07 '17 at 11:58

2

You can access the post by primary key

post = Post.objects.get(id=id)
post.is_activate = True
post.save()

by this code your is_activate flag will be set for this post

answered Feb 07 '17 at 11:58

SHIVAM JINDAL

2,844
1
17
34

You mean create a new view function to set the variable or I need to do this in the same function that I retrieve each individual post? – Italo Lemos Feb 07 '17 at 12:03
1

in the same function – SHIVAM JINDAL Feb 07 '17 at 12:23

score 1 · Answer 2 · answered Feb 07 '17 at 12:22

Try this: This is your model.py

class Post(models.Model):
   title = models.CharField(max_length=250)
   slug = models.SlugField(max_length=250)
   body = models.TextField()
   is_activate = models.BooleanField(default=False)

and view.py

from foldername import Post //if there are subfolders use'.' between them.
//import the other packages which u need
form=form_name  //your form name
template=template_name  //your template name
def post( self, request, *args, **kwargs ):
        try:
            form = self.form_class( request.POST)
            if form.is_valid():
            new_formfile = form.save(commit=False)
            new_formfile.is_activate = true
            new_formfile.save()
        except Exception as e:
            return render(request, 'exception.html', {'exception': str(e), 'message': e.message})

OR

//another method write in try block

id = request.GET.get('id')
id_instance = Post.objects.get( pk = id )
form = self.form_class(request.POST, instance = id_instance)
if form.is_valid():
new_formfile = form.save(commit=False)
new_formfile.is_activate = true
new_formfile.save()
form.save()

score 0 · Answer 3 · answered Jul 18 '22 at 11:30

0

With "update()", you can update "is_activate" field as shown below:

Post.objects.filter(id=id).update(is_activate=True)

answered Jul 18 '22 at 11:30

Super Kai - Kazuya Ito

22,221
10
124
129

How to modify a boolean field model in Django?

3 Answers3