65

I was wondering if there was a way to change a button's style, in css, after it's been clicked, so not a element:active.

CalvT
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JohnyNich
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9 Answers9

94

If you're looking for a pure css option, try using the :focus pseudo class.

#style  {
    background-color: red;
}

#style:focus {     
    background-color:yellow;    
}
Rich
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67

Each link has five different states: link, hover, active, focus and visited.

Link is the normal appearance, hover is when you mouse over, active is the state when it's clicked, focus follows active and visited is the state you end up when you unfocus the recently clicked link.

I'm guessing you want to achieve a different style on either focus or visited, then you can add the following CSS:

a { color: #00c; }
a:visited { #ccc; }
a:focus { #cc0; }

A recommended order in your CSS to not cause any trouble is the following:

a
a:visited { ... }
a:focus { ... }
a:hover { ... }
a:active { ... }

You can use your web browser's developer tools to force the states of the element like this (Chrome->Developer Tools/Inspect Element->Style->Filter :hov): Force state in Chrome Developer Tools

Harsha Laxman
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MrD
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  • In most cases using the anchor tags :visited state will be the cleanest css only implementation of a button with a clicked state. You could also repurpose a checkbox :checked http://jsfiddle.net/4hrzf39g/2/ but its a bit much imo. – luckyape Apr 08 '19 at 21:30
  • "focus follows active" is not ... very clear – bharal Feb 17 '21 at 00:24
14

It is possible to do with CSS only by selecting active and focus pseudo element of the button.

button:active{
    background:olive;
}

button:focus{
    background:olive;
}

See codepen: http://codepen.io/fennefoss/pen/Bpqdqx

You could also write a simple jQuery click function which changes the background color.

HTML:

<button class="js-click">Click me!</button>

CSS:

button {
  background: none;
}

JavaScript:

  $( ".js-click" ).click(function() {
    $( ".js-click" ).css('background', 'green');
  });

Check out this codepen: http://codepen.io/fennefoss/pen/pRxrVG

Mikkel Fennefoss
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13

Try to check outline on button's focus:

button:focus {
    outline: blue auto 5px; 
}

If you have it, just set it to none.

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    This was the only solution that worked for me. The border property was not enough, it was outline that fixed the issue. – BrianLegg Feb 08 '19 at 22:07
7

What is the code of your button? If it's an a tag, then you could do this:

a {
  padding: 5px;
  background: green;
}
a:visited {
  background: red;
}
<a href="#">A button</a>

Or you could use jQuery to add a class on click, as below:

$("#button").click(function() {
  $("#button").addClass('button-clicked');
});
.button-clicked {
  background: red;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button id="button">Button</button>
CalvT
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3

If your button would be an <a> element, you could use the :visited selector.

You are limited however, you can only change:

  • color
  • background-color
  • border-color (and its sub-properties)
  • outline-color
  • The color parts of the fill and stroke properties

I haven't read this article about revisiting the :visited but maybe some smarter people have found more ways to hack it.

Paul van den Dool
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1

An easy way of doing this is to use JavaScript like so:

element.addEventListener('click', (e => {
    e.preventDefault();

    element.style = '<insert CSS here as you would in a style attribute>';
}));
Crabby Fish
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1

all answers is true for hover, focus,... if you want change background-color when you click and be stay that clicked state, you could do this:

<!DOCTYPE html>
<html>
  <head>
  </head>
  <body>
  </body>
  <script>
    const element = document.querySelector("body")
    let taskDone = false
   
    // function for show button
    const elementShow = () => {
      element.innerHTML = `
        <button id="done-button" style="background-color : ${!taskDone 
          ? "#4dd432" : "#fd67ad"};" onclick=doneTask()>
          ${!taskDone ? "Done" : "not done yet"}
        </button>
        `
    }
    elementShow()

    // click Done button
    const doneTask = () => {
      taskDone = (taskDone ? false : true)
      elementShow()
    }
  </script>
</html>
maryam
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0

You can do it with :focus.

.button {
  border: 1px solid black;
}

.button:focus {
  border: 1px solid red;
}