Chrome console prints out function source code instead of doing something

Question

I'm trying to make a simple blackjack game on Javascript. I really don't understand why the function does not work properly?

var OurHand = 0;
var TheirHand = 0;

function dealCards() {
    OurHand += Math.floor(Math.random() * 10) + 1
    OurHand += Math.floor(Math.random() * 10) + 1
    TheirHand += Math.floor(Math.random() * 10) + 1
    TheirHand += Math.floor(Math.random() * 10) + 1
}

did you remember the parenthesis? use `dealCards()` not `dealCards` — Keatinge, Feb 09 '17 at 16:35
yes I call it "dealCards" in the console, and the variables do not change at all. — Petras Vilkelis, Feb 09 '17 at 16:39
you need to call it with the parenthesis `()`. See the example below. — DominikAngerer, Feb 09 '17 at 16:40

score 0 · Answer 1 · answered Feb 09 '17 at 16:37

0

You will have to execute your code using functionName() with parenthesis. Here is your example working & writing "done" in the console as an result.

var OurHand = 0;
var TheirHand = 0;

function dealCards() {
    OurHand += Math.floor(Math.random() * 10) + 1
    OurHand += Math.floor(Math.random() * 10) + 1
    TheirHand += Math.floor(Math.random() * 10) + 1
    TheirHand += Math.floor(Math.random() * 10) + 1
    console.log('Done dealing cards.')
}

dealCards() // this will execute your code of the dealCards function

console.log(OurHand)
console.log(TheirHand)

answered Feb 09 '17 at 16:37

DominikAngerer

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But don't I execute it in the console by typing "dealCards" ? – Petras Vilkelis Feb 09 '17 at 16:41
nope :) you can read more about that here: http://www.w3schools.com/js/js_function_invocation.asp or here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Function/call – DominikAngerer Feb 09 '17 at 16:42

Chrome console prints out function source code instead of doing something

1 Answers1