sorting list of values in java after converting string to integer

Question

I am doing some selenium automation test case and i am getting list of web element using the below code.

List<WebElement> list = GlobalVariables.BrowserDriver.findElements(By.xpath(".//*[@id='Tbls_T']/tbody/tr/td[4]"));

and then i am iterating that web element and getting the values using

for (WebElement webElement : list) {

        System.out.println(webElement.getText());

}

so i am getting the values in string format. and sample values are giving below

-100,000 -80,000 0.100 2 87.270 3,000.000

I want to check these values in sorting order or not? for that i think i should convert to integer and then check using some kind of sorting method i guess. for that i have tried to convert the values to a list of integer and then use some sorting algorithm like Guava to check the sorting. because of negative values i am facing difficulty to do that.

Is there any way i can check the sorting order for the above problem and check the order of the values. ?

thanks in advance.

Guava is not a sorting algorithm! Anyway, are you on *Java 8*? — Chetan Kinger, Feb 09 '17 at 16:48
I am on java 7 . ok i saw that i can check the list is sorted or not using Guava. sorry if i am wrong. — asl, Feb 09 '17 at 16:52
no values are not unique.. it changes. its just sample which i have. — asl, Feb 09 '17 at 16:53
You can't convert these to `int` because you'll lose the decimal part in some of them. See this answer http://stackoverflow.com/questions/11973383/how-to-parse-number-string-containing-commas-into-an-integer-in-java — JeffC, Feb 09 '17 at 17:32
Possible duplicate of [How to parse number string containing commas into an integer in java?](http://stackoverflow.com/questions/11973383/how-to-parse-number-string-containing-commas-into-an-integer-in-java) — JeffC, Feb 09 '17 at 17:33
I don't see why you need to sort the values to check if they're sorted. Can't you just compare each value with its previous and check the number is not smaller? — Gary - Stand with Ukraine, Feb 09 '17 at 17:43

score 0 · Answer 1 · answered Feb 09 '17 at 16:58

0

create 2 copies of your data
convert the first to integers and sort it
convert the second one to integers and leave it
check if the two lists are equal if they are then your list is sorted

answered Feb 09 '17 at 16:58

Méhdi Màick

157
3
7

i cannot convert to integer because of the negative values. getting exception. for example i am getting -100,000 and i tried this to convert this value Integer.parseInt(-100,000); but getting exception because of '-' – asl Feb 09 '17 at 17:05
that's because their not integers here is a solution : String s ="-100,000"; s = s.replaceAll(",","."); //to replace , with . s = Double.parseDouble(s); this should fix it – Méhdi Màick Feb 09 '17 at 17:11

score 0 · Answer 2 · answered Feb 09 '17 at 17:09

Please use another list of doubles and Collections.sort(). You may have to remove the commas from strings

public class ConvertToIntSort 
{
    public static void main( String[] args ) 
    {

       String[] strlist = {"-100000","0.100", "2" , "3000.000","87.270", "-80000" };
       java.util.List<String> stringlist =  Arrays.asList(strlist);
       java.util.List<Double> intList = new ArrayList<Double>();
       for(String str : stringlist)
       {          
         //converting and adding to double list  
         intList.add(Double.valueOf(str));

       }
        //Sorting is done here            
        Collections.sort(intList);

       for(Double num : intList)
       {
           System.out.println(num);         

       }

    }
}

Sumit Kumar · Accepted Answer · 2017-02-09T18:09:17.323

You want to just check the incoming list is sorted or not. You compare the previous value with current value. If previous value is greater than current value then the list is not sorted.

Sample code:

    WebElement prev=null;
    boolean isSorted = true;
    for (WebElement currentWebElement : list) {

        if (prev == null) {
            prev = currentWebElement;
            continue;
        } else {

            if (Double.compare(Double.parseDouble(prev.getText().replaceAll(",", "")),
                    Double.parseDouble(currentWebElement .getText().replaceAll(",", ""))) > 0) {
                isSorted = false;
                break;
            }

            prev = currentWebElement;

        }

    }

perfect.. this worked well.. thank you so much for the help Sumit. — asl, Feb 09 '17 at 18:48

sorting list of values in java after converting string to integer

3 Answers3