Different ways to create objects on stack

Question

There is a class with a non-default constructor.

#include <iostream>

class Foo {

public:

  Foo(int a) { std::cout << "Constructor" << std::endl; };

}

So the default constructor couldn't be invoked:

   Foo obj; // compilation error

The non-default constructor can be inkoved:

   Foo obj(1);

Question:

What happens in the following line that compiles?

   Foo obj();

[The most vexing parse](https://en.wikipedia.org/wiki/Most_vexing_parse). — R Sahu, Feb 10 '17 at 06:28

Kupto · Accepted Answer · 2017-02-10T06:20:14.623

4

You create a function prototype with no parameters.

To be more specific... basically nothing happens

edited Feb 10 '17 at 06:20

answered Feb 10 '17 at 06:18

Kupto

See also "C Forward Declaration" – awiebe Feb 10 '17 at 06:20
2

Well something happens, you said that function exists, so you're gonna get strange link-time errors if you accidentally manage to invoke it and haven't provided an implementation. – awiebe Feb 10 '17 at 06:24
sure, but during execution nothing happens, no construction, no stack allocation, nottin, the line has no effect – Kupto Feb 10 '17 at 06:26

1 Answers1