How to apply If condition for following result?

Question

echo of $res showing following result:-

stdClass Object ( [permissionId] => 23 [roleId] => 14 [view] => 0 [add] => 0 [edit] => 0 [deleteRole] => 0 [status] => 1 [moduleId] => 1 )

I have tried like something below

if($res->view = 1 or $res->add = 1 or $res->edit = 1 or $res->deleteRole = 1 ){ 
     echo "condition true";
} else {
     echo "condition false";
}

But it always echo condition true. Is if condition is right? Please help me how to write if condition.

Answer 1

change to == Comparison Operator, if you put = it always true, the assignment operator always return true

Answer 2

Actually you are not comparing, you are just doing assignment. = used for assignment not for comparison.

So use == instead of =

if($res->view == 1 or $res->add == 1 or $res->edit == 1 or $res->deleteRole == 1 ){ 
         echo "condition true";
    } else {
         echo "condition false";
    }

OR

if($res->view == 1 || $res->add == 1 || $res->edit == 1 || $res->deleteRole == 1 ){ 
     echo "condition true";
} else {
     echo "condition false";
}

Note:- Rest it's up-to-you what you want to compare and in which manner. So adjust code accordingly.Thanks

Answer 3

Give == (Comparison operator) rather than = (Assignment operator) and ||

if(($res->view == 1) || ($res->add == 1) || ($res->edit == 1) || ($res->deleteRole == 1) ){ 
     echo "condition true";
} else {
     echo "condition false";
}