Python - Regex match last key/value into dictionary string

Question

I read this dictionary from a file as a string:

string = '{"key1":"value1", "key2":"value2"}'

I don't know which values key1 and key2 can assume, I need to access the value of the last pair written on the string (in this case 'value2'). So converting it into a python dictionary is out of the question since it would probably change the order.

I've tried something like:

value = re.search(r'"(.*?)":"(.*?)"', string)

But I don't know how to access the .group(2) of the last match.

[`ast.literal_eval`](https://docs.python.org/3/library/ast.html#ast.literal_eval). — Abdou, Feb 13 '17 at 18:32
why should the order matter? why isn't this data coming in as a list? — , Feb 13 '17 at 18:35
See the accepted answer at the question I marked as a dupe, I think it's much saner than a regexp. — Peter DeGlopper, Feb 13 '17 at 18:37

score 1 · Accepted Answer · answered Feb 13 '17 at 18:36

1

You can do this :

import re
output = re.findall(".*\"[a-zA-Z0-9]+\"[\w]*:[\w]*\"(.+)\"[\w]*}", string)

Output :

>>> re.findall(".*\"[a-zA-Z0-9]+\"[\w]*:[\w]*\"(.+)\"[\w]*}", string)
['value2']

answered Feb 13 '17 at 18:36

Jarvis

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Python - Regex match last key/value into dictionary string

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