How to build a third list by comparing two other list with string matching.

Question

The answer to my question is probably somewhere around here but I couldn't find it.

I have a two lists :

['batman','superman','spiderman',]
['batman','ironman','superman','flash','wonderwoman']

I want to compare the two lists and return the matching elements as a third list :

['batman','superman']

I only found this solution:

list=['a cat','a dog','a yacht']
string='a cat'
if string in list:
  print 'found a cat!'

But it's only a comparison between a string and a list...

come on, you did not search that much. There are sooo many duplicates. one-liner: `set(list1).intersection(list2)` is one. — Jean-François Fabre, Feb 15 '17 at 14:50

score 2 · Accepted Answer · answered Feb 15 '17 at 14:49

2

Use intersection,

l1 = ['batman','superman','spiderman',]
l2 = ['batman','ironman','superman','flash','wonderwoman']

print(set(l1).intersection(set(l2)))
#set(['batman', 'superman'])

answered Feb 15 '17 at 14:49

SparkAndShine

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How to build a third list by comparing two other list with string matching.

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