Returning from if statement within function giving undefined

Question

My assumption is that the return in the first part of the if statement would break the function and return n, however it keeps giving undefined. If I console.log n it gives me the correct thing. Am I missing something??

Thanks everybody

 function digital_root(n) {
   if(n.toString().length === 1){
    console.log(n)
    return true;
  }else{
    var digits = (""+n).split("");
    thing = digits.reduce((a, b) => Number(a) + Number(b), 0);
    digital_root(thing)
  }
}

digital_root(942)

You have to return something in the `else` statment! `return digital_root(thing);` will do! — ibrahim mahrir, Feb 15 '17 at 22:42

score 0 · Answer 1 · answered Feb 15 '17 at 22:42

0

You do not return in the recursion so that means it will return undefined.

return digital_root(thing)

answered Feb 15 '17 at 22:42

epascarello

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...and, of course, the OP also needs to return `n` (instead of `true`) from the innermost function call. – Ilmari Karonen Feb 15 '17 at 22:57
Awesome! Thank you so much. I'm still trying to grasp Javascript recursion... – Slagathor The Destroyer Feb 15 '17 at 23:01

Returning from if statement within function giving undefined

1 Answers1