Iterate over string starting at a specific character

Question

I have a string that is a repeating decimal. The string value may or may not have values to the left of the decimal: ".33333333" or "1.6666666666" or "12125.464646464646".

I want to iterate through the string starting directly after the decimal. Is there a way to start a for loop directly to the right of the decimal?

Ideally, you would not cut or split the string in advance. The question is more geared towards starting a for loop at a specific point given a specific character versus looping through a full string that has been cut.

.333333 would start at 3

1.66666 would start at 6

12125.464646 would start at 4

Possible duplicate of [Split a string by a delimiter in python](http://stackoverflow.com/questions/3475251/split-a-string-by-a-delimiter-in-python) — Anomitra, Feb 17 '17 at 07:12
@AnomitraSaha I wasn't looking to split MYGz got what I was looking for — Mazzone, Feb 17 '17 at 07:14
@MYGz @AnomitraSaha That's equivalent to `str.split` in that it creates a copy of the decimal digits. — SwiftsNamesake, Feb 17 '17 at 07:48
@Mazzone `for a in s.split['.'][1]:` is the exact equivalent of what @MYGz wrote. — Anomitra, Feb 17 '17 at 10:29

score 0 · Answer 1 · answered Feb 17 '17 at 07:08

0

There are many ways to do this. One possible way is to use find(),

inp = "12125.464646464646"
for x in xrange(inp.find('.')+1, len(inp)):
  print inp[x],

Also you can try,

inp = "12125.464646464646"
for a in inp[inp.find('.')+1:]:

answered Feb 17 '17 at 07:08

Fallen

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Maybe point the OP in the direction of the Python docs? Teach a man to fish and all that faff... – SwiftsNamesake Feb 17 '17 at 07:36
Teach a person the method name and they can google it themselves. – Fallen Feb 17 '17 at 07:40
I didn't mean the docs of this method in particular. Just the Python docs overall (like a more polite way of saying RTFM). – SwiftsNamesake Feb 17 '17 at 07:44

score 0 · Answer 2 · answered Feb 17 '17 at 07:10

0

Try with split,

a="12125.464646464646"
for i in a.split('.')[-1]:
     print i

answered Feb 17 '17 at 07:10

Rahul K P

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score 0 · Answer 3 · answered Feb 17 '17 at 08:55

0

Hi try this simplified code

 a="12125.464646464646"
 print [i for i in a.split('.')[1]]
 #output:- ['4', '6', '4', '6', '4', '6', '4', '6', '4', '6', '4', '6']

answered Feb 17 '17 at 08:55

Hilar AK

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Iterate over string starting at a specific character

3 Answers3