I'm rather new to Java and I was making a simple calculator. Problem is when I my input number is for example "3.1" it gives an exception error, but when writing "3,1" it works just fine.
My friend, however, has a slightly more advanced calculator (with string parsing) and when I run his code the opposite happens: 3,1 gives exception error, 3.1 works perfectly.
I was looking forward to know what causes these different behaviors.
I made this simple sum just now and the same happens, I'll edit and put his calculator code in a few minutes
import java.util.Scanner;
public class Tutorial_7 {
public static void main(String args[]){
Scanner scan = new Scanner(System.in);
double num1, num2;
System.out.println("Introduza os dois números");
System.out.println("1º: ");
num1 = scan.nextDouble();
System.out.println("2º: ");
num2 = scan.nextDouble();
System.out.println((num1 + num2));
scan.close();
}
}
Final edit: He does use Double.parseDouble()
. Got it, the difference is indeed in where it is localized. Should have looked for it but never heard of this concept before.
Thank you