How do I Make my String into an int in Python 3? Am I doing this wrong?

Asked Feb 20 '17 at 19:51

Active Feb 20 '17 at 19:58

Viewed 31 times

This seems like a problem that is easy to find on the internet, but nothing fixes the problem. I am creating a dice rolling program that lets you choose the number of dice you want to roll, but it keeps giving me an error when I type anything that's not an integer: 'ValueError: invalid literal for int() with base 10'

Here's my code:

print("Dice Rolling Simulator 1.0") 
def functionStart():
    diceAmount = input("How many dice would you like to roll? (we recomend less than 6): ")
    if int(diceAmount) == int:
        print("true")
    else:
        print("Please enter a number such as '3' or '7'. It is not rocket science")
        functionStart()

functionStart()

I'm simply trying to verify that they typed an integer. The converted number will also be used to generate the number of dice rolled later in the program. What am I doing wrong?

asked Feb 20 '17 at 19:51

`if int(diceAmount) == int` is wrong. if not integer you'll get `ValueError` – Jean-François Fabre Feb 20 '17 at 19:52
`if int(diceAmount) == int:` what do you expect this to be doing? – Ryan Haining Feb 20 '17 at 19:53
ok, how do I fix it? – Feb 20 '17 at 19:53
int(diceAmmount) casts value to integer. You do not want it. You need to check the type of variable. refer to this question http://stackoverflow.com/questions/402504/how-to-determine-the-variable-type-in-python – Sergii Khaperskov Feb 20 '17 at 19:54
just use diceAmount.isnumeric(). this will return true if diceAmount is an integer number. False otherwise. – Prateek Dewan Feb 20 '17 at 19:55
`def functionStart(): try: diceAmount = int( input("How many dice would you like to roll? (we recomend less than 6): ")): print("true") : catch ValueError: print("Please enter a number such as '3' or '7'. It is not rocket science") : functionStart() – Martin Bonner supports Monica Feb 20 '17 at 19:55
I expect "if int(diceAmount) == int:" to check if the input is an integer and not a string or float. – Feb 20 '17 at 19:55
Use "if type(diceAmmount) is int:" – Sergii Khaperskov Feb 20 '17 at 19:57
http://pastebin.com/skg99eJF – Ryan Haining Feb 20 '17 at 19:59
Thanks @PrateekDewan , that Fixed it. – Feb 20 '17 at 20:02

How do I Make my String into an int in Python 3? Am I doing this wrong?

0 Answers0