Index a tuple by calling one of its elements

Question

I'm trying to write a function that takes in

a list of tuples with partygoers names and their priority and
the max number of people that can get it. I'm currently trying to put tuples in ascending order based on one of its elements.

I have a list or tuples:

 alist =[('Carlos', 1), ('Gretchen', 8), ('Abby', 6),('Sam', 4)]

so far Ive made a list of all of the numbers in order with this code:

 def party_time(alist,maxnum):
     newlist = []
     finallist=[]
     while len(finallist) < maxnum:
        for tup in alist:
            rank = tup[1]
            newlist.append(rank)
        newlist.sort()

 newlist = [1,4,6,8]

Is there a way to use a for loop to go through newlist and index the tuple by using the number in newlist? Or will it just index where the number is in the tuple?

`sorted(alist, key=lambda x: x[1])` should get your items sorted. You may need reverse as well. — sberry, Feb 21 '17 at 04:17
Possible duplicate of [Sort a list by multiple attributes?](http://stackoverflow.com/questions/4233476/sort-a-list-by-multiple-attributes) — Steven Summers, Feb 21 '17 at 04:19

score 0 · Answer 1 · answered Feb 21 '17 at 05:05

0

This should do it:

def party_time(alist, maxnum):
    sorted_list = sorted(alist, key=lambda p: p[1], reverse=True)
    return sorted_list[:maxnum]

answered Feb 21 '17 at 05:05

Lucas

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Index a tuple by calling one of its elements

1 Answers1