I was trying to figure out how to remove only a certain character from a string that appears more than once.
Example:
>>>x = 'a,b,c,d'
>>>x = x.someremovingfunction(',', 3)
>>>print(x)
'a,b,cd'
If anyone can help, that would be greatly appreciated!
Split the original string by the character you want to remove. Then reassemble the parts in front of the offending character and behind it, and recombine the parts:
def remove_nth(text, separator, position):
parts = text.split(separator)
return separator.join(parts[:position]) + separator.join(parts[position:])
remove_nth(x,",",3)
# 'a,b,cd'
Assuming that the argument 3 means the occurence of the character in question, you could just iterate over the string and count. When you find the occurence just create a new string without it.
def someremovingfunction(text, char, occurence):
pos = 0
for i in text:
pos += 1
if i == char:
occurence -= 1
if not occurence:
return text[:pos-1] + text[pos:]
return text
Usage example:
print someremovingfunction('a,b,c,d', ',', 3)
This may help
>>> x = 'a,b,c,d'
>>> ''.join(x.split(','))
'abcd'
