take all data between tow line with regex

Question

I read all topics about that but there is no solution for me.

I wanna take all data between two line. For ex:

<!-- DETAILS-->

            <li><span>xxxx</span></li>
            <li><span>xxxx</span></li>
            <li><span>xxxx</span></li>
            <li><span>xxxx/span></li>
            <li><span>xxxx</span></li>
            <li><span>xxxx</span></li>
            <li><span>xxxx</span></li>

 <!-- ###DETAILS -->

I tried start end patterns and another regex codes but I can't find solution. My problem I wanna print everything between DETAILS and need your help.

you should use an xml/html parser instead of regex: http://stackoverflow.com/questions/1732348/regex-match-open-tags-except-xhtml-self-contained-tags — krock, Feb 25 '17 at 13:15
Please [edit] your question and include all your attempts. This shouldn’t be too hard. — Sebastian Simon, Feb 25 '17 at 13:15

Maciej Kozieja · Answer 1 · 2017-02-25T13:33:00.337

You can try this: ((?:\n|.)*) and read 2nd capture group. But it will not work for nested tags

import java.util.regex.Matcher;
import java.util.regex.Pattern;

final String regex = "<!--\\s*(\\S+)\\s*-->((?:\\n|.)*)<!--\\s*###\\1\\s*-->";
final String string = "<!-- DETAILS-->\n\n"
     + "            <li><span>xxxx</span></li>\n"
     + "            <li><span>xxxx</span></li>\n"
     + "            <li><span>xxxx</span></li>\n"
     + "            <li><span>xxxx/span></li>\n"
     + "            <li><span>xxxx</span></li>\n"
     + "            <li><span>xxxx</span></li>\n"
     + "            <li><span>xxxx</span></li>\n\n"
     + " <!-- ###DETAILS -->";

final Pattern pattern = Pattern.compile(regex);
final Matcher matcher = pattern.matcher(string);

while (matcher.find()) {
    System.out.println("match: " + matcher.group(1));
}

This will match evrything between  and 

take all data between tow line with regex

1 Answers1