remove quote on echo json_encode();

Question

 $result = mysql_query("SELECT * FROM $tableName WHERE id=1");               
 $array = mysql_fetch_array($result); 
 $help_name = $array['name'];
 $req =   $array['req'];
 //fetch result    

 echo json_encode($help_name);

Problem is I'm getting the result with double quotes, how to remove the double quotes

use `htmlspecialchars($str, ENT_QUOTES)` [PHP.net - Function htmlspecialchars](http://php.net/manual/en/function.htmlspecialchars.php) — Abdul Rafay, Feb 28 '17 at 12:49
That's the only way that your string will be valid json. If you don't want quotes, don't encode it to json. — jeroen, Feb 28 '17 at 12:53
Please refer [http://stackoverflow.com/questions/13938645/remove-double-quote-in-json-encode] [http://stackoverflow.com/questions/8837659/remove-double-quotes-from-a-json-encoded-string-on-the-keys] — Mani7TAM, Feb 28 '17 at 12:54
Possible duplicate of [Remove double quote in json\_encode()](http://stackoverflow.com/questions/13938645/remove-double-quote-in-json-encode) — Masivuye Cokile, Feb 28 '17 at 12:59
@MasivuyeCokile - IMHO, this is not a duplicate. The linked question is more complex. It involves removing double-quotes from certain items within json_encoded data. This question is much simpler: it is simply the quotes around the whole string, when passing to `echo`. — ToolmakerSteve, Oct 06 '19 at 14:30

score 10 · Accepted Answer · answered Feb 28 '17 at 13:03

10

Try trim in php

<?php 
$name = "Aman";
$str = json_encode($name);
echo trim($str, '"');  // output : Aman
?>

answered Feb 28 '17 at 13:03

Aman Kumar

4,533
3
18
40

score 1 · Answer 2 · answered Feb 28 '17 at 12:52

1

$help_name = preg_replace('/"([^"]+)"\s*:\s*/', '$1:', $help_name);

answered Feb 28 '17 at 12:52

Mani7TAM

469
3
10

remove quote on echo json_encode();

2 Answers2

Try trim in php

Linked