I am still fairly new to JS, and I am trying to replace the HTML of a div with a picture that is being moused over, and when the mouse leaves I want it to return to it's normal state. I thought that I did everything right but my code doesn't seem to be working. I've looked through stack overflow and I see a lot of jQuery solutions to my 'problem,' but I would like an answer in pure JavaScript (I'm trying to "maser" this first), along with an explanation so I can understand why the answer IS the answer. Thanks.
I'll try to explain myself (my code). I grabbed reference to the image holder, and I grabbed reference to the the images. I thought I made a function that looped through the array of images and added an event listener to whichever image ( image[i] ) was being moused over. Then, I added an event listener that is supposed to return the image holder to it's default state by inserting the original HTML. I just don't understand how to fix this.
var holder = document.getElementById('holder');
var images = document.getElementsByTagName('img');
var popImage = function () {
for (i = 0; i < images.length; i++) {
images[i].addEventListener('mouseover', = function () {
holder.innerHTML = images[i];
});
images[i].addEventListener('mouseout', function () {
holder.innerHTML =
'<div class='col-md-3 img-fluid' id='img1'><img src='photo1.jpg'></div>
<div class='col-md-3 img-fluid' id='img2'><img src='photo2.jpg'></div>
<div class='col-md-3 img-fluid' id='img3'><img src='photo3.2.jpg'></div>
<div class='col-md-3 img-fluid' id='img4'><img src='photo4.jpg'></div>'
});
};
};
popImage();