How to get file name during filter in Tomcat Server while sending the file through curl command

Question

I am trying to send a csv,png,gzip etc. files into my server . In order to process these files it needs to be filtered based on the proper extension ( csv,png,gzip).

If I can get the filename then I can parse it to get the extension. This is the way i am sending file:

curl -u user:password -H "Transfer-Encoding: chunked" -T file_name_location -v --noproxy server_name -X POST http://server_name:8080/

I am new to java servlet. I tried printing the httprequest but unable to do so.

    public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {

    HttpServletRequest httpRequest = (HttpServletRequest) request;
    HttpServletResponse httpResponse = (HttpServletResponse) response;

    System.out.println("The http request is " + httpRequest );

I cannot send any header except "Tranfer-encoding" in curl command. That is the limitation. Thanks

I cannot send any header except "Tranfer-encoding" in curl call. That is the limitation, i forget to mention in the question. — user2044000, Mar 01 '17 at 08:06
use -F instead of -T ? for example, curl -F upload=@aaa.png url. Then you can use apache.commons.fileupload to get file name easily — Howard Wang, Mar 01 '17 at 08:49

score 0 · Answer 1 · edited May 23 '17 at 12:09

0

You can pass the file name in the URL as a query parameter, i.e.:

http://my-server/some/path?filename=foo.bar

...or in a HTTP header. See here: How to send a header using a HTTP request through a curl call?

edited May 23 '17 at 12:09

Community

1
1

answered Mar 01 '17 at 08:06

vstrom coder

297
1
8

I cannot send any header except "Tranfer-encoding" in curl call. That is the limitation, i forget to mention in the question. – user2044000 Mar 01 '17 at 08:08
Use the first method then - passing the file name as a query parameter in the URL – vstrom coder Mar 01 '17 at 08:10
That is not working. It is asking for headers for particular file-format. I have to get this done in the code where filter is built. – user2044000 Mar 01 '17 at 08:12
Not sure I understand, what component is asking for headers? is that your code? – vstrom coder Mar 01 '17 at 08:54
Yes thats the code part of filter... Once i will receive the file, then i am trying to print the content of the httprequest. – user2044000 Mar 01 '17 at 09:17
Suppose you want to decompress the file then you will use "Content-Encoding=gzip" but I am not allowed to use this header. I have to get the filename for this. – user2044000 Mar 01 '17 at 09:18
So can you get the filename from the url parameter as I suggested? – vstrom coder Mar 01 '17 at 11:37
Sorry, I couldn't get the filename. – user2044000 Mar 01 '17 at 11:58
There is nothing in the code other than which is given in question. – user2044000 Mar 10 '17 at 09:48
I want to get the filename through Servlet request. – user2044000 Mar 10 '17 at 09:49

How to get file name during filter in Tomcat Server while sending the file through curl command

1 Answers1