How do we pass JSONObject as string in getJSONArray();?

Question

I want to fetch multiple JSONArray from an JSONObject

JSONObject jsonObject=new JSONObject(response_view); 
for(int x=0; x<jsonObject.length(); x++) {  
 JSONArray jsonArray = jsonObject.getJSONArray("Here I have to pass");
}

This is my JSON,

{
    "Mr. VICKRAM SINGH_269": [{
        "status": "P",
        "date": "2017-02-05"
    }, {
        "status": "P",
        "date": "2017-02-06"
    }],
    "Mr. VIVEK KUMAR YADAV_276": [{
        "status": "P",
        "date": "2017-02-05"
    }, {
        "status": "P",
        "date": "2017-02-06"
    }]
}

http://stackoverflow.com/a/42530742/7320259 please check my answer. this question have JSON too — Zaki Pathan, Mar 01 '17 at 12:25
{"Mr. VICKRAM SINGH_269":[{"status":"P","date":"2017-02-05"},{"status":"P","date":"2017-02-06"}],"Mr. VIVEK KUMAR YADAV_276":[{"status":"P","date":"2017-02-05"},{"status":"P","date":"2017-02-06"}]} — Rishabh Saxena, Mar 01 '17 at 12:39
Data is Dynamic we have to use indexing..but dont Know how we pass — Rishabh Saxena, Mar 01 '17 at 12:40
you need to change your JSON Response. you cant get this data easily — Zaki Pathan, Mar 01 '17 at 12:41
In your Previous example stackoverflow.com/a/42530742/7320259 array name is static but I am having Dynamic array — Rishabh Saxena, Mar 01 '17 at 12:42
In that example "dados" is the array key so it is easily done — Zaki Pathan, Mar 01 '17 at 12:44
yes it easily done but my array key is Dynamic that is the problem and i dont know the Specific name as it is dynamic — Rishabh Saxena, Mar 01 '17 at 12:48

Chetan Joshi · Accepted Answer · 2017-03-01T13:36:56.027

1

you can parse Json like below:

try{
    JSONObject json = new JSONObject(jsonRespondeString);
    Iterator<String> iterator =  json.keys();
    while (iterator.hasNext()){
           String key =  iterator.next();
           JSONArray jsonArray = json.getJSONArray(key);
           for(int i=0;i<jsonArray.length();i++){
               JSONObject object = jsonArray.getJSONObject(i);
               String value1 = object.getString("key1");
               String value2 = object.getString("key2");
            }
        }
    }
 catch (JSONException e){
      e.printStackTrace();
}

you can get name and id from key like this:

String str="Mr. VICKRAM SINGH_269";
String array[]=  str.split("_");
String name =array[0];
String id =array[1];

edited Mar 01 '17 at 13:36

answered Mar 01 '17 at 12:28

Chetan Joshi

5,582
4
30
43

JSON Array is Dynamic...it change time to time.. All JSON Array is store in JSON object from which I have to fetch – Rishabh Saxena Mar 01 '17 at 12:37
post your json Response – Chetan Joshi Mar 01 '17 at 12:40
@RishabhSaxena see my edited code – Chetan Joshi Mar 01 '17 at 12:43
I think this helps @RishabhSaxena you can get your key here String key = iterator.next(); – Zaki Pathan Mar 01 '17 at 12:46
Thank you I find My solution.....I also Want to remove Digits in Student name please help me – Rishabh Saxena Mar 01 '17 at 13:33
@RishabhSaxena see my updated answer fro your name and digit problem. pass key of array in place of str – Chetan Joshi Mar 01 '17 at 13:37

score 0 · Answer 2 · answered Mar 01 '17 at 12:28

0

JSONArray jsonArray=jsonObject.getJSONArray("Write the name of your array here");

and then loop your jsonArray Object

answered Mar 01 '17 at 12:28

anzaidemirzoi

386
4
13

array is dynamic...I dont know the name of an array – Rishabh Saxena Mar 01 '17 at 12:35
post your JSON @RishabhSaxena – Zaki Pathan Mar 01 '17 at 12:37
{"key":["item","item2","item3"]} you should have a key for your array in json string, as it is 'key' here. otherwise, your json is not a valid json. Could you please post your json string? – anzaidemirzoi Mar 01 '17 at 12:38
{"Mr. VICKRAM SINGH_269":[{"status":"P","date":"2017-02-05"},{"status":"P"‌,"date":"2017-02-06"‌}],"Mr. VIVEK KUMAR YADAV_276":[{"status":"P","date":"2017-02-05"},{"status":"P"‌,"date":"2017-02-06"‌}]} Array is Dynamic so we cannot fetch using name of it – Rishabh Saxena Mar 01 '17 at 12:52

How do we pass JSONObject as string in getJSONArray();?

2 Answers2